MSP430FR5994 current consumption in LPM3 mode cannot go down to 0.7uA

Hi,

I am using the MSP430FR5994 LaunchPad. And make FR5994 working at LPM3 mode. I removed all the connections between the FET and MSP430FR5994, except the GND and 3V3. And test the current on 3V3 while the FR5994 is running the LPM3 example code. The current is nearly 2mA. Is there any solutions to fix this problem. Thanks!

The code is here,

#include <msp430.h>

int main(void)
{
    // VLOCLK, ~1s interrupts
    WDTCTL = WDTPW | WDTTMSEL | WDTSSEL_2 | WDTIS_5;
    SFRIE1 |= WDTIE;                        // Enable WDT interrupt

    // Configure GPIO
    P1OUT = 0;
    P1DIR = 0xFF;

    P2OUT = 0;
    P2DIR = 0xFF;

    P3OUT = 0;
    P3DIR = 0xFF;

    P4OUT = 0;
    P4DIR = 0xFF;

    P5OUT = 0;
    P5DIR = 0xFF;

    P6OUT = 0;
    P6DIR = 0xFF;

    P7OUT = 0;
    P7DIR = 0xFF;

    P8DIR = 0xFF;
    P8OUT = 0;

    PJOUT = 0;
    PJDIR = 0xFFFF;

    // Disable the GPIO power-on default high-impedance mode to activate
    // previously configured port settings
    PM5CTL0 &= ~LOCKLPM5;

    // Clock System Setup
    CSCTL0_H = CSKEY_H;                     // Unlock CS registers
    CSCTL1 = DCOFSEL_0;                     // Set DCO to 1 MHz
    CSCTL2 = SELM__DCOCLK | SELS__DCOCLK | SELA__VLOCLK;
    CSCTL3 = DIVA__1 | DIVS__1 | DIVM__1;   // Set all dividers to 1
    CSCTL4 = LFXTOFF | HFXTOFF;
    CSCTL0_H = 0;                           // Lock CS registers

    P1DIR |= BIT0;                          // Turn on LED

    __bis_SR_register(LPM3_bits | GIE);
    __no_operation();                       // For debugger
}

// Watchdog Timer interrupt service routine
#if defined(__TI_COMPILER_VERSION__) || defined(__IAR_SYSTEMS_ICC__)
#pragma vector=WDT_VECTOR
__interrupt void WDT_ISR(void)
#elif defined(__GNUC__)
void __attribute__ ((interrupt(WDT_VECTOR))) WDT_ISR (void)
#else
#error Compiler not supported!
#endif
{
    P1OUT ^= BIT0;                          // Toggle P1.0 (LED)
}